Version

3.1.0-beta.2

Steps to reproduce

Syntax Error: TypeError: Cannot read property 'content' of null when you declare two emits with different parameters

If only one DefineEmit exists at the same time, how do you distinguish between the type and number of arguments

import { defineProps, defineEmit, useContext } from 'vue'

const emitClose = defineEmit<(e: 'close', id: number) => void>() const emitShow = defineEmit<(e: 'show', name: string, age: number) => void>()

emitClose('close', 1) emitShow('show', '1', 18)

What is expected?

DefineEmit can exist more than one at a time

What is actually happening?

DefineEmit can have multiple errors at the same time

const emit = defineEmit<((e: 'close', id: number) => void) | ((e: 'show', name: string, age: number) => void)>()
emit('close', 1)
emit('show', '1', 18)

I tried to write it this way, but I got the same error

这样写传入的就不是一个函数类型了吧 //Syntax Error: TypeError: Cannot read property 'content' of null //type argument passed to defineEmit() must be a function type or a literal type with call signatures

const emit = defineEmit<(e: 'close', id: number) => void | ((e: 'show', name: string, age: number) => void)>()

这样写的话当我emit('show', '1', 18) 时可以触发事件 但是会有如下两个错误 vetur 会报错Expected 2 arguments, but got 3

控制台也会输出Component emitted event "show" but it is neither declared in the emits option nor as an "onShow" prop.

@yanbowe

这样：

const emit = defineEmit<{(e: 'close', id: number): void; (e: 'show', name: string, age: number): void}>()
emit('close', 1)
emit('show', '1', 2)